auto x (photo x auto) = ??

[CannaDaTaBiz]

So if i have an female F1 mix between auto and photo(ofc af trait hidden), and then pollinate it with auto male. Does this significantly increase the % of autos in next generation, compared to just making F2 seeds with photo x auto?

Would the auto gene get hidden again and require me to make F2 with them also before more auto % came out, or would it be like skipping to F3 seeds in terms of auto %, or perhaps half being like auto x photo F3 and half being like f2?

I know it would not get the qualities of photo as much, but i could also do this easily on the side of other things and if it does significantly increase the af% in next generation, it could be worth doing.

Thanks in advance

 

[Proph]

Auto x Photo = F1 Photo period plants...
25% of the f2's will be autos
50% percent of the f3's will be autos
100% of the f4's will be auto..

If you plan on pollinating at f2, you have to grow out a bunch of plants and find the ones that auto and pollinate one of those with the auto pollen. That will take you to full auto.. But the genetic potential is cut very short because you would be skipping levels. You may not get the traits you want until f3 or f4, but you will never know if you take short cuts.

 

[CannaDaTaBiz]

Auto x Photo = F1 Photo period plants...
25% of the f2's will be autos
50% percent of the f3's will be autos
100% of the f4's will be auto..

If you plan on pollinating at f2, you have to grow out a bunch of plants and find the ones that auto and pollinate one of those with the auto pollen. That will take you to full auto.. But the genetic potential is cut very short because you would be skipping levels. You may not get the traits you want until f3 or f4, but you will never know if you take short cuts.

This is not what i was asking.

Im asking this:

First i have a photo that has been pollinated with autoflower. These make F1 seeds. I grow one of these F1 seeds(it does not autoflower i know, only had the auto gene hidden) but i would pollinate it with another strain that is normal 100% autoflower.

When comparing these seeds that come out of this pollination. Do they have more AF than F2 auto x photo, or how would it go? I know how it works if i keep making new generations between the auto x photo mix, but if i introduce pure AF to non autoflowering auto x photo F1 cross, you know?

 

[Bob's Auto's]

Nonoo... when @Proph says the F2 from an auto x photo you get 25% auto. It means that the auto trait is recessive. This means that in the F1 there is 50% that has the recessive trait and 50% does not... if you pick the wrong plants to cross you don't get an auto @F3, but again 50% with and 50% without the recessive auto trait.

 

[Bob's Auto's]

when crossing to get a ressive trait to show you always have to keep going until you see the trait appearing. Then you know the plant has it in it's genetics.

 

[Bob's Auto's]

If you want to read up on the topic follow this link

 

[CannaDaTaBiz]

Nonoo... when @Proph says the F2 from an auto x photo you get 25% auto. It means that the auto trait is recessive. This means that in the F1 there is 50% that has the recessive trait and 50% does not... if you pick the wrong plants to cross you don't get an auto @F3, but again 50% with and 50% without the recessive auto trait.

Im still not asking about photo x auto crosses taken to new generations, but about introducing 100% pure different AF male pollen to non autoflowering photo x auto F1 mix female. So that the resulting baby is 75% AF genes 25% photo genes, but its mother did not autoflower, because it had those genes hidden.

I know backcrossing an photo x auto F2 that autoflowers to original AF being used, it gives more AF than just doing F3 and selecting for autoflowers.

First i have a photo that has been pollinated with autoflower. These make F1 seeds. I grow one of these F1 seeds(it does not autoflower i know, only had the auto gene hidden) but i would pollinate it with another strain that is normal 100% autoflower.

When comparing these seeds that come out of this pollination. Do they have more AF than F2 auto x photo, or how would it go? I know how it works if i keep making new generations between the auto x photo mix, but if i introduce pure AF to non autoflowering auto x photo F1 cross, you know?

 

[Proph]

In that case, what you are asking, makes no sense to do. The f1 seeds of an auto crossed to a photo will be f1 seeds that are photoperiods (because the af gene is recessive).. If you grow out and pollinate one of those f1s with pollen from an entirely different auto, you're making an entirely new F1, that will not auto flower. It's taking a step backwards.. You are introducing a new recessive trait to the gene pool instead of trying to bring out (or find) the auto gene that is already there. This is why I said if you do it at f2 it could work. You should read up on punnett squares and Mendels law for more info on how genetic probabilty works.

 

[CannaDaTaBiz]

In that case, what you are asking, makes no sense to do. The f1 seeds of an auto crossed to a photo will be f1 seeds that are photoperiods (because the af gene is recessive).. If you grow out and pollinate one of those f1s with pollen from an entirely different auto, you're making an entirely new F1, that will not auto flower. It's taking a step backwards.. You are introducing a new recessive trait to the gene pool instead of trying to bring out (or find) the auto gene that is already there. This is why I said if you do it at f2 it could work. You should read up on punnett squares and Mendels law for more info on how genetic probabilty works.

Is this correct use of this square?

Here photo x auto F2

Here auto x (photo x auto)

If not, could you show me how to put them on this properly? https://scienceprimer.com/punnett-square-calculator



Edit. i accidentally had parent 2 trait 1 as AA instead of Aa

 

[Proph]

Is this correct use of this square?

Here photo x auto F2
View attachment 1231387


Here auto x (photo x auto)
View attachment 1231388

If not, could you show me how to put them on this properly? https://scienceprimer.com/punnett-square-calculator

This particular type of chart is for those who have an understanding of how genetics work. I was suggesting that you read up on punnett squares and mendels law. No point in using a graph if you dont have an understanding of it. It seems you may be looking for short cuts. I don't take short cuts so I may not be the best person to help. And no, that chart does not seem to be set up correctly.. Autoflowers should be represented by two lower case variables (aa for example), while the dominate photo period should be represented by to capitalized variables (BB for example). I don't see that anywhere on the chart posted. It also starts with photo x auto f2.. I'm not sure what that is or what it means. I thought your question was about the f1 seeds being pollinated by an auto.. It took me almost a year to get a complete understanding of how breeding autos worked. Unfortunately I can't pass that type of knowledge on to you through a post. I would start reading info on how genetic traits are passed on and how recessive traits work... Then ask as many questions as needed. But to answer your original question, if you cross a photo to an auto the f1 seeds will all be photo period plants with a recessive auto gene.. If you grow out those f1's and pollinate a female with a pollen from a new af male, you are making a new F1 with even more recessive traits. Doing this does not progress the line forward or get you any closer to full auto. It just introduces more traits that you may need to breed out before taking it to full auto. Auto breeding isn't quick, and isn't easy. Taking short cuts can results in autos that don't autoflower, or they autoflower, but don't have any of the other traits you wanted, like yield, smell, bag appeal ect. But again, pollinating the f1 female plants with a new af male, would create a new f1. It would not increase the percentage of autoflower plants.